Digital Electronics NUMBER SYSTEM BINARY CODES BOOLEAN ALGEBRA K MAPS COMBINATIONAL CKT SEQUENTIAL CIRCUITS INTRODUCTION CLOCK BISTABLE MULTIVIBRATOR DERIVATION of FLIPFLOP circuit RS FLIPFLOP RS FLIPFLOP(NAND IMPLEMENTATION) R'S' FLIPFLOP Clocking RS LATCH Other LATCHes Timing problem in LATCHES ASYNCHRONUS INPUTS Parameters of CLOCK pulse QUESTIONS(LATCH using MUX) EDGE SENSITIVE LATCH (i.e. FLIPFLOP) MASTER SLAVE FF D FF USING MUX TIMING PARAMETERS OF FF CHARACTERISTIC EQUATIONS OF FFs EXCITATION TABLES OF FF CONVERSION OF 1 FF TO OTHER FF as 1bit MEMORY CELL REGISTERS SHIFT REGISTERS RING COUNTER JOHNSON COUNTER QUESTION(Serial Data transfer) ASYNCHRONOUS COUNTERS RIPPLE COUNTER COUNTER other than MOD-2n Designing COUNTER Using K-MAPS QUESTION(MOD 6 counter) QUESTION(Counter design) DOWN COUNTER QUESTION(Counter design) GLITCH SYNCHRONOUS COUNTER COMPARISON B/W SYNC. & ASYNC. COUNTERS CLOCK SKEW QUESTION(Maximum frequency question) QUESTION(Maximum frequency question) MORE QUESTIONS TIMING CIRCUITS

QUESTION

Q- Find the maximum clock frequency of the above circuit if specifications of the flip-flop are as T (setup) = 5ns     T (hold time) = 4ns             T (CLK to Q) = 9ns and maximum delay of the combinational circuit is T (c-delay) = 13 ns. There is a clock skew of +3ns for 2nd FF in the above circuit.

Ans: We firstly represent the delays wrt edge of 1st FF as

And the delayed input must reach before the edge reaches 2nd flip-flop

The clock skew is basically the delay in clock signal reaching 2nd flip-flop. Hence this is quiet similar to the previous question of a buffer in the pathway of clock.

Hence Clock time period is T = T CLK to Q + cdelay + Setup time – Clock Skew

= 9 + 13 + 5 – 3 = 24 ns

And maximum frequency of the circuit is F max = 1 / 24 = 4.16 MHz