For a number system with base r (with r > 1), there are two types of compliments:
- r’s compliment
- (r-1) ‘s compliment
r’s Compliment: If we have a positive number N with integer part of n digits then we define r’s compliment as
10’s compliment of number (5432) 10 is 104– 5432 = 10000 – 5432 = (4568) 10
[value of n is 4]
10’s compliment of number (0.5432) 10 is 100– 0.5432 = 1 – 0.5432 = (0.4568) 10
[value of n is 0 as there is no integer part in this number]
10’s compliment of number (54.32) 10 is 102– 54.32 = 100 – 54.32 = (45.68) 10 [value of n is 2]
2’s compliment of number (110.01) 2 is (23)2– 110.012= 1000 – 110.01 = 001.11 [value of n is 3]
Eg. Find 2’s compliment of (110.01) 2 (value from above example)
Ans: Following the rule we get the answer as 000.1110
(r-1) ‘s compliment: If we have a positive number N with base r and integer part with digits n and fractional part of m digits, we define (r-1) ‘s compliment as rn – r-m– N
9’s compliment of number (5432) 10 is 104– 100 – 5432 = 10000 – 1 – 5432 = (4567) 10
[Value of n is 4 and of m is 0]
9’s compliment of number (0.5432) 10 is 100– 10-4 – 0.5432 = 1 – 0.0001 – 0.5432 = (0.4567) 10
[Value of n is 0 as there is no integer part in this number and of m is 4]
9’s compliment of number (54.32) 10 is 102 – 10-2 – 54.32 = 100 – 0.01 – 54.32 = (45.67) 10 [Value of n is 2 and of m is 2]
1’s compliment of number (110.01) 2 is (23)10– (2-2)10 – 110.012= 1000 – 0.01 – 110.01 = 001.10 [Value of n is 3 and of m is 2]
Applying the rule to above example we get the answer as 001.10, the sameJ
Relation between the r’s Compliment and (r-1) ‘s compliment: We can get r’s Compliment from (r-1) ‘s compliment by just adding r-m and vice-versa by subtracting r-m
Compliment of compliment: If we take r’s compliment of r’s compliment we get the original number as
Let the original number be N
So r’s compliment is rn – N and compliment of compliment is rn – (rn – N) = N which is the original number
and the same is for (r-1) ‘s compliment.
Let the original number be N
So r’s compliment is rn – r-m – N and compliment of compliment is rn – r-m – (rn – r-m – N ) = N which is the original number
1’s compliment and 2’s compliment: Following table would show the representation of decimal -7 to +8 in 1’s and 2’s compliment. In the signed number , we take the 4th bit as signed bit and make this bit one(‘1’) when ever we have negative number & make it zero(‘0’) when we have a positive number and rest of the 3 bits are used to represent magnitude.
Comparison of 1’s compliment and 2’s compliment:
- 1’s compliment is easier to implement than 2’s compliment
- While for the subtraction, 2’s compliment is better because for 2’s compliment we need only 1 arithmetic operation while 2 arithmetic operations are needed for 1’s compliment.
- 2’s compliment has only one representation for zero while 1’s compliment has two representation for zero as shown above
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