To implement the function F(A, B, C, D)= Σ (1, 2, 5, 7, 9, 14) using MUX using different variable as selection variable. Let’s now take the variable A for input lines and B, C & D for selection lines. N=4 so MUX is 2 N-1= 23 = 8 to 1 So min terms with A in compliment form are 0 […]
Tag: questions
Q: Implement function using MUX
e.g. To implement the function F(A, B, C)= Σ (1, 2, 5, 7) using MUX using different variable as selection variable. Let’s now take the variable B for input lines and A & C for selection lines. The min terms with B in compliment form are 0, 1, 4, 5 and the min terms with B in un-complimented form are […]
Q: Boolean function Implementation using MUXes
Q-How to implement any Boolean function using MUX? Ans: While implementing any function using MUX, if we have N variables in the function then we take (N-1) variables on the selection lines and 1 variable is used for inputs of MUX. As we have N-1 variables on selection lines we need to have 2 N-1 to 1 […]
Q: HIGHER MUXes from LOWER MUXes
Q- Implement (a) 8 to 1 MUX (b) 16 to 1 MUX using 4 to 1 MUX. Ans: (a) Select lines are abc2 Following is the 8 to 1 multiplexer from 4 to 1 multiplexer (b)Select lines are abcd2 Following is the circuit for 16 to 1 MUX
Q: Implement the Octal to Binary encoder
Q- Implement the Octal to Binary encoder (only first 8 numbers). Ans: In this circuit, we have 8 inputs and 3 outputs. The octal number is feed into the encoder by placing a high (1) on the corresponding line and we get the binary equivalent as output. From the above truth table we can easily get […]
Q: HIGHER DECODER from LOWER DECODERS
Q- Obtain a 4 to 16 decoder using (a) 2 to 4 decoder (b) 3 to 8 decoder Ans: (a) we take abcd2 as the input to the decoder. Following is the diagram to design 4 to 16 decoder using 2 to 4 decoders When we have a=0 b=0 then top most decoder is enabled and 1 […]
Q: Implement Full Adder using DECODER
Q- Implement the Full adder using 3 to 8 decoder. Ans: equation for sum S = ab’c’ + a’b’c + a’bc’ + abc = Σ(1,2,4,7) C = ab + ac + bc = ab(c + c’) + ac (b + b’) + bc (a + a’) = abc + abc’ + abc + ab’c + […]
Q2: Obtaining HIGHER COMPARATOR using LOWER COMPARATOR
Q- Implement the function of 10-bit comparator using 4-bit comparators. Ans: We can implement this as follow:
Obtaining HIGHER COMPARATOR using LOWER COMPARATORS
Q-Can we implement higher comparator 4-bit comparator using 2-bit comparators. Ans: Yeswe can implement the above required as follow: Firstly lower two bits of A & B are compared and then next bits and then next. We feed the result of first 2 bits to lower bit of next comparator. Then we feed the result […]
Question: 4-bit ADDER and SUBTRACTOR in a SINGLE CIRCUIT
Q- Implement the 4-bit ADDER and SUBTRACTOR in a single circuit where we select one of the two using a select pin SEL. Ans: The following circuit would work as required: In this circuit we use property of XOR gate by which XOR gate acts as a inverter when we have one input as 1. When sel = […]