Q1. Find out the parity bit (odd) for message 1100
As 1100 has 2 i.e. even number of 1’s so we take parity bit (odd) as 1 to make odd number of 1’s out of 5 bits
So message we send is 11001 (5th is the parity bit)
Q2. Find out the parity bit (even) for message 1100
As we have 2 i.e. even number of 1’s so we take parity bit (even) as 0 so that number of 1’s remain even. Hence the message is 11000 (5th is the parity bit)
Q3. Find out the parity bit (even) for message 1000
As we have 1 i.e. odd number of 1’s so we take parity bit (even) as 1 so that number of 1’s as even. Hence the message is 10001 (5th is the parity bit)
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