Combinational Circuits

Q9: Implement 4to1 MUX using 2to1 MUX

Q- Can we implement 4 to 1 MUX using (a) three 2 to 1 MUX (b) only two 2 to 1 MUX and a OR gate & NOT gate?

Ans: (a) We can implement 4 to 1 MUX from 2 to 1 MUX as shown below:

(b) We have already implemented 8 to 1 MUX using two 4 to 1 MUX and one 2 to 1 MUX but as here we have to implement without using 2 to 1 MUX but a OR gate hence we’ll utilize Enable pin of the MUX and skip the use of 2 to 1 MUX as shown below:

Whenever E pin is HIGH, that MUX is selected

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